8z^2-40z^2+56z=0

Solution for 8z^2-40z^2+56z=0 equation:

8z^2-40z^2+56z=0

We add all the numbers together, and all the variables

-32z^2+56z=0

a = -32; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·(-32)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*-32}=\frac{-112}{-64}
=1+3/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*-32}=\frac{0}{-64}
=0
$